SICP 問題 5.34
反復的階乗手続きをコンパイルし,再帰版との本質的な違いを示せ.
反復的階乗手続きの内容を説明する.
(compile '(define (factorial n) (define (iter product counter) (if (> counter n) product (iter (* counter product) (+ counter 1)))) (iter 1 1)) 'val 'next)
コンパイルして,説明をつけた.
((env) (val) ( ;; 手続きを構成し,本体のコードを飛び越す (assign val (op make-compiled-procedure) (label entry18) (reg env)) (goto (label after-lambda19)) ;; factorialの呼び出しの開始. entry18 ;; procの環境をenvに代入 (assign env (op compiled-procedure-env) (reg proc)) ;; factorialの実引数をfactorialの引数nと対応づけて環境を拡張 (assign env (op extend-environment) (const (n)) (reg argl) (reg env)) ;; 内部定義に進む.valを(compiled-procedure entry20 env)の形にする. (assign val (op make-compiled-procedure) (label entry20) (reg env)) (goto (label after-lambda21)) entry20 (assign env (op compiled-procedure-env) (reg proc)) ;; product counterをそれぞれ1に束縛した環境を作る (assign env (op extend-environment) (const (product counter)) (reg argl) (reg env)) ;; 手続き本体の開始 (save continue) (save env) ;; (> counter n)の計算 (assign proc (op lookup-variable-value) (const >) (reg env)) (assign val (op lookup-variable-value) (const n) (reg env)) (assign argl (op list) (reg val)) (assign val (op lookup-variable-value) (const counter) (reg env)) (assign argl (op cons) (reg val) (reg argl)) (test (op primitive-procedure?) (reg proc)) (branch (label primitive-branch25)) ;ここに飛ぶ. compiled-branch26 (assign continue (label after-call27)) (assign val (op compiled-procedure-entry) (reg proc)) (goto (reg val)) primitive-branch25 (assign val (op apply-primitive-procedure) (reg proc) (reg argl)) ;; (> counter n)の次 after-call27 ;valには(> couner n)の値が入っている (restore env) ;手続き本体のenvとcontinueを復帰 (restore continue) (test (op false?) (reg val)) (branch (label false-branch23)) ;; (> counter n)がtrueの時,productの値をvalに入れて,大本のcontinueへ. true-branch22 (assign val (op lookup-variable-value) (const product) (reg env)) (goto (reg continue)) ;; (> counter n)がfalseの時 false-branch23 (assign proc (op lookup-variable-value) (const iter) (reg env)) ;; (+ counter 1)を計算するためにcontinue, proc, envを退避 (save continue) (save proc) (save env) ;; (+ counter 1)の計算開始 (assign proc (op lookup-variable-value) (const +) (reg env)) (assign val (const 1)) (assign argl (op list) (reg val)) (assign val (op lookup-variable-value) (const counter) (reg env)) (assign argl (op cons) (reg val) (reg argl)) (test (op primitive-procedure?) (reg proc)) (branch (label primitive-branch31)) ;ここへジャンプ compiled-branch32 (assign continue (label after-call33)) (assign val (op compiled-procedure-entry) (reg proc)) (goto (reg val)) ;; (+ counter 1)を実際に計算 primitive-branch31 (assign val (op apply-primitive-procedure) (reg proc) (reg argl)) after-call33 (assign argl (op list) (reg val)) ;arglに今計算した値をリストにして代入 (restore env) ;大本の環境の復帰 (save argl) ;(+ counter 1)の結果のリストを退避 ;; (* counter product)の計算開始 (assign proc (op lookup-variable-value) (const *) (reg env)) (assign val (op lookup-variable-value) (const product) (reg env)) (assign argl (op list) (reg val)) (assign val (op lookup-variable-value) (const counter) (reg env)) (assign argl (op cons) (reg val) (reg argl)) (test (op primitive-procedure?) (reg proc)) (branch (label primitive-branch28)) ;ここへジャンプ compiled-branch29 (assign continue (label after-call30)) (assign val (op compiled-procedure-entry) (reg proc)) (goto (reg val)) ;; (* counter product)を実際に計算 primitive-branch28 (assign val (op apply-primitive-procedure) (reg proc) (reg argl)) after-call30 (restore argl) ;(+ counter 1)の復帰 (assign argl (op cons) (reg val) (reg argl)) ;arglに((* counter product) (+ counter 1))を代入 (restore proc) ;iterを復帰 (restore continue) ;呼び出し元に返るcontinueを復元 (test (op primitive-procedure?) (reg proc)) (branch (label primitive-branch34)) ;ジャンプしない compiled-branch35 (assign val (op compiled-procedure-entry) (reg proc)) ;entry20へのラベルをvalに代入 (goto (reg val)) primitive-branch34 (assign val (op apply-primitive-procedure) (reg proc) (reg argl)) (goto (reg continue)) after-call36 after-if24 ;; entry18からジャンプ after-lambda21 ;; iterを(compiled-procedure entry20 env)と定義. (perform (op define-variable!) (const iter) (reg val) (reg env)) (assign val (const ok)) ;; ここから(iter 1 1)の処理. (assign proc (op lookup-variable-value) (const iter) (reg env)) (assign val (const 1)) ;; arglは(1)になる (assign argl (op list) (reg val)) (assign val (const 1)) (assign argl (op cons) (reg val) (reg argl)) ;argl => (1 1) (test (op primitive-procedure?) (reg proc)) ;=>false (branch (label primitive-branch37)) compiled-branch38 ;; valにiterに対応付けられてるラベルを代入する (assign val (op compiled-procedure-entry) (reg proc)) ;; entry20へgoto (goto (reg val)) primitive-branch37 (assign val (op apply-primitive-procedure) (reg proc) (reg argl)) (goto (reg continue)) after-call39 after-lambda19 (perform (op define-variable!) (const factorial) (reg val) (reg env)) (assign val (const ok)) ))
反復的階乗計算では次の繰り返しに行く前に引数の計算が行われ,環境や継続はすべて大本の状態に復元してから次の繰り返しに向かう.
前の問題で見たように再帰的階乗計算ではprocとenvを退避させ,さらに戻ってくる場所をcontinueによって保持し続けないといけない.
そのために繰り返しが増えるほどにスタックが深くなっていく.